可調避震的一堆問題... - 機車

By Cara
at 2009-03-01T12:11
at 2009-03-01T12:11
Table of Contents
打完再吃飯好了~~
有些腳踏車的避振(可能機車也有)
還會考慮到煞車或是加速,往前(往後)壓縮的力量
所以考慮像下面這種受力方式
u2 往左或往右
我 | f2(t)
是 |__┌───┐
|__│ m |
| └┼─┼┘
牆 | ╲ │ f1(t)往上
壁 | ╱ │
╲ │ u1往上或是往下
======================================我是地板
如果看物體的左右平衡圖
kx(x-u2) f2往右
往左 __┌───┐
__│ m |
└┼─┼┘
Cx(x'-u2')
往右
因為單純考慮x方向,也就是水平方向,我們完全不考慮y方向(垂直方向)的受力
平衡方程式很快的可以寫出如下
mx" + cxX' + kxX = f2(t) + kxu2 + Cxu2'
然後如果看物體的上下平衡圖
完全只考慮y方向,也就是考慮垂直方向,x方向(水平方向)的受力完全不考慮
┌───┐
│ m | f1(向上)
└┼─┼┘
ky(y-u1) Cy(y-u1)
平衡方程式接著寫出如下
my" + CyY' +kyY = f1(t) + kyu2 + Cyu2'
小寫的x還有y代表下標
單純顯示運動方向而已~~
--
有些腳踏車的避振(可能機車也有)
還會考慮到煞車或是加速,往前(往後)壓縮的力量
所以考慮像下面這種受力方式
u2 往左或往右
我 | f2(t)
是 |__┌───┐
|__│ m |
| └┼─┼┘
牆 | ╲ │ f1(t)往上
壁 | ╱ │
╲ │ u1往上或是往下
======================================我是地板
如果看物體的左右平衡圖
kx(x-u2) f2往右
往左 __┌───┐
__│ m |
└┼─┼┘
Cx(x'-u2')
往右
因為單純考慮x方向,也就是水平方向,我們完全不考慮y方向(垂直方向)的受力
平衡方程式很快的可以寫出如下
mx" + cxX' + kxX = f2(t) + kxu2 + Cxu2'
然後如果看物體的上下平衡圖
完全只考慮y方向,也就是考慮垂直方向,x方向(水平方向)的受力完全不考慮
┌───┐
│ m | f1(向上)
└┼─┼┘
ky(y-u1) Cy(y-u1)
平衡方程式接著寫出如下
my" + CyY' +kyY = f1(t) + kyu2 + Cyu2'
小寫的x還有y代表下標
單純顯示運動方向而已~~
--
Tags:
機車
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