坡度與下滑力之觀念是否正確 - 單車
By Delia
at 2016-11-08T23:03
at 2016-11-08T23:03
Table of Contents
設計教材,請各位幫忙看看本人的觀念是否正確。
請先看圖,這是假設一個15%的坡。
https://c2.staticflickr.com/6/5519/30559116620_72cd7aff47_b.jpg
根據公路坡度定義,15%的坡為水平距離100公尺,垂直距離上升15公尺。
因此我畫了一個底邊100 : 高15 : 斜邊101.12 的直角三角形。
並假設騎士+單車的質量為M公斤(kg)正在騎這個坡。
向下的重力為M公斤重(kgw)
=> 沿斜面向下的分力是 M / 101.12 * 15 kgw
= 0.148 Mkgw
這樣的力,能讓質量M的騎士+單車,往下坡方向有 0.148 * 9.8 m/s^2 的加速度
= 1.45m/s^2的加速度,每秒鐘速度增加1.45m/s
= 每秒鐘速度增加 1.45 * 60 * 60 / 1000 km/hr
= 每秒鐘速度增加 5.23公里/小時
這樣對嗎?? 謝謝
--
請先看圖,這是假設一個15%的坡。
https://c2.staticflickr.com/6/5519/30559116620_72cd7aff47_b.jpg
根據公路坡度定義,15%的坡為水平距離100公尺,垂直距離上升15公尺。
因此我畫了一個底邊100 : 高15 : 斜邊101.12 的直角三角形。
並假設騎士+單車的質量為M公斤(kg)正在騎這個坡。
向下的重力為M公斤重(kgw)
=> 沿斜面向下的分力是 M / 101.12 * 15 kgw
= 0.148 Mkgw
這樣的力,能讓質量M的騎士+單車,往下坡方向有 0.148 * 9.8 m/s^2 的加速度
= 1.45m/s^2的加速度,每秒鐘速度增加1.45m/s
= 每秒鐘速度增加 1.45 * 60 * 60 / 1000 km/hr
= 每秒鐘速度增加 5.23公里/小時
這樣對嗎?? 謝謝
--
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